Tuesday, October 27, 2015

Hardy-Weinberg c:

Given: q2=.384
  • With what was given, we can find q by taking the square root of .384 which is .619.
  • From q, we can find p by subtracting .619 from 1.00 which is .381.
  • We can square p to find p2, which is .145.
  • With all of the information we have, we can find 2pq by multiplying 2 times p times q which is .471.

What does it mean?
  • What was given was q2, which is the frequency of homozygous recessive individuals.
  • From that we got q, which is the frequency of recessive alleles.
  • Then we found p, which is the frequency of dominant alleles.
  • From p we found p2, which is the frequency of homozygous dominant individuals.
  • Once we found 2pq, we found the frequency of heterozygous individuals.